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What would happen to a reversible dissoc...

What would happen to a reversible dissociation reaction at equilibrium when an inert gas is added while the pressure remains unchanged ?

A

Less of the product will be formed

B

More of the product will be formed

C

More of thereactants will be fromed

D

It remains unaffected.

Text Solution

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The correct Answer is:
To answer the question of what happens to a reversible dissociation reaction at equilibrium when an inert gas is added while the pressure remains unchanged, we can follow these steps: ### Step 1: Understand the Reaction Consider a reversible dissociation reaction represented as: \[ A \rightleftharpoons B + C \] In this reaction, A dissociates into products B and C. ### Step 2: Define the Conditions When we add an inert gas to the system, we are increasing the total number of moles of gas in the container. However, since the pressure is kept constant, this means that the volume of the container must increase to accommodate the added gas. ### Step 3: Analyze the Effect on Concentration The concentration of each component in the reaction is defined as the number of moles divided by the volume. Since we are increasing the volume (to keep pressure constant), the concentration of all gases, including A, B, and C, will decrease. ### Step 4: Apply Le Chatelier's Principle Le Chatelier's Principle states that if a system at equilibrium is subjected to a change, the system will adjust itself to counteract that change and restore a new equilibrium. In this case, since the concentration of products (B and C) decreases due to the increase in volume, the equilibrium will shift to the right to produce more products in order to counteract the decrease in concentration. ### Step 5: Conclusion Thus, when an inert gas is added while keeping the pressure constant, the equilibrium will shift towards the products (B and C), resulting in the forward reaction being favored. This means that more of the products will be formed until a new equilibrium is established. ### Final Answer The reaction will shift to the right, producing more products (B and C) in response to the decrease in concentration due to the increase in volume. ---
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