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Calculate the percentage of hydrolysis i...

Calculate the percentage of hydrolysis in 0.003 M aqueous solution of NaOCN. `K_a` for HOCN `= 3.33 xx 10^(-4) M` .

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NaOCN is a salt of weak acid-strong base. Hence,
`K_(h) = (K_(w))/(K_(a))=(10^(-14))/(3.3xx10^(-4))=(10^(-10))/(3.33) :. H= sqrt((K_(h))/(c))=sqrt((10^(-10))/(3.33)xx(1)/(3xx10^(-3)))=sqrt(10^(-8))=10^(-4)`
`:.` % age hydrolysis `= 10^(-4)xx100=0.01`
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