The solubility product for silver choride is `1.2xx10^(-10)` at 298 K. Calculate the solubility of silver chloride at 298 K.

Explanation

To calculate the solubility of silver chloride (AgCl) at 298 K given its solubility product (Ksp) of \(1.2 \times 10^{-10}\), we can follow these steps:

### Step-by-Step Solution:

1. **Write the Dissociation Equation:**
Silver chloride (AgCl) dissociates in water as follows:
\[
\text{AgCl (s)} \rightleftharpoons \text{Ag}^+ (aq) + \text{Cl}^- (aq)
...