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Calculate the pH in a solution that is 0...

Calculate the pH in a solution that is `0.1M` in acetic acid and `0.1M` in benozic acid. `K_(a) for C H_(3)COOH` and `C_(6)H_(5)COOH are 1.8xx10^(-5)` and `6.5xx10^(-5)` respectively.

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`[H_(3)O^(+)]=sqrt((1.8xx10^(-5))(0.1)+(6.5xx10^(-5))(0.1))`
`=sqrt(1.8xx10^(-6)+6.5xx10^(-6))=sqrt(8.3xx10^(-6))=2.88xx10^(-3)M`
pH `=-log [H_(3)O^(+)]=- log (2.88xx10^(-3))=3-0.4594=2.5406`.
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