pH of a solution of `CuSO_(4)` is.......... Than 7 and that of solution of `Na_(2)CO_(3)` is ..........than 7 .

Answer

To solve the question regarding the pH of solutions of `CuSO4` and `Na2CO3`, we need to analyze the nature of these compounds based on their acidic and basic properties.

### Step-by-Step Solution:

1. **Identify the Nature of `CuSO4`:**
- `CuSO4` (Copper(II) sulfate) is a salt formed from the reaction of a weak base (Cu(OH)2) and a strong acid (H2SO4).
- Since it is derived from a strong acid, the solution of `CuSO4` will exhibit acidic properties.

2. **Determine the pH of `CuSO4`:**
- The pH of a solution of a salt from a strong acid and a weak base is less than 7. This is because the strong acid component dominates the solution's behavior.
- Therefore, we can conclude that the pH of a solution of `CuSO4` is **less than 7**.

3. **Identify the Nature of `Na2CO3`:**
- `Na2CO3` (Sodium carbonate) is a salt formed from the reaction of a strong base (NaOH) and a weak acid (H2CO3).
- Since it is derived from a strong base, the solution of `Na2CO3` will exhibit basic properties.

4. **Determine the pH of `Na2CO3`:**
- The pH of a solution of a salt from a strong base and a weak acid is greater than 7. This is because the strong base component dominates the solution's behavior.
- Therefore, we can conclude that the pH of a solution of `Na2CO3` is **greater than 7**.

### Final Answer:
- The pH of a solution of `CuSO4` is **less than 7**.
- The pH of a solution of `Na2CO3` is **greater than 7**.