Conc. `HNO_(3)` on dehydration with `P_(4)O_(10)` gives…………

Answer

To solve the question "Conc. HNO₃ on dehydration with P₄O₁₀ gives…", we can follow these steps:

### Step 1: Understand the Reactants
- **Concentrated HNO₃**: This is nitric acid, which contains a high concentration of nitric acid (around 68%).
- **P₄O₁₀ (Phosphorus Pentoxide)**: This is a strong dehydrating agent, meaning it removes water from other substances.

### Step 2: Identify the Reaction
When concentrated HNO₃ is treated with P₄O₁₀, the dehydrating agent (P₄O₁₀) removes water from the nitric acid.

### Step 3: Determine the Product
The dehydration of concentrated HNO₃ leads to the formation of **Nitrogen Pentoxide (N₂O₅)**. The reaction can be summarized as follows:

\[ 4 \, \text{HNO}_3 \xrightarrow{\text{P}_4\text{O}_{10}} 2 \, \text{N}_2\text{O}_5 + 4 \, \text{H}_2\text{O} \]

### Step 4: Write the Final Answer
Thus, the product formed when concentrated HNO₃ is dehydrated with P₄O₁₀ is **Nitrogen Pentoxide (N₂O₅)**.

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