The P-P-P angle in `P_(4)` molecule is …………..degree while S-S-S angle in `S_(8)` is ………..degree.

Answer

To solve the question regarding the P-P-P angle in the `P4` molecule and the S-S-S angle in the `S8` molecule, we will analyze the structures of both molecules step by step.

### Step 1: Understanding the Structure of P4
- The molecule `P4` (white phosphorus) has a tetrahedral structure. In this structure, the phosphorus atoms are arranged in a way that they form a tetrahedron.
- Each phosphorus atom is bonded to three other phosphorus atoms.

### Step 2: Determining the P-P-P Bond Angle in P4
- In a tetrahedral structure, the bond angles between the atoms are approximately 109.5 degrees. However, due to the specific arrangement of the atoms in `P4`, the bond angles between the phosphorus atoms (P-P-P) are actually 60 degrees.
- Therefore, the P-P-P bond angle in `P4` is **60 degrees**.

### Step 3: Understanding the Structure of S8
- The molecule `S8` (elemental sulfur) has a crown-like structure, which can be visualized as a cyclo-octasulfur ring.
- In this structure, the sulfur atoms are arranged in a cyclic manner, forming a crown shape.

### Step 4: Determining the S-S-S Bond Angle in S8
- In the crown structure of `S8`, the bond angles between the sulfur atoms (S-S-S) are not as straightforward as in a tetrahedral structure. The bond angles in the crown structure are approximately 107 degrees.
- Therefore, the S-S-S bond angle in `S8` is **107 degrees**.

### Final Answer
- The P-P-P angle in `P4` is **60 degrees**.
- The S-S-S angle in `S8` is **107 degrees**.