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Why does R(3)P=O exist but R(3)N=O does ...

Why does `R_(3)P=O` exist but `R_(3)N=O` does not (R is an alkyl group )?

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N due to the absence of d-orbitals, connot form `ppi-dpi` multiple bonds. As a result, N cannot expand its covalency beyond four but in `R_(3)N=O`, has a covalency of 5. Therefore, the compound `R_(3)N=O` does not exist. In contrast, P due to the presence of d-orbitals forms `ppi-dpi` multiple bands and hence can expand its covalency 4. Therefore, P forms `R_(3)P=O` in which the covalency of P is 5.
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