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Give the disproportionation reaction of ...

Give the disproportionation reaction of `H_(3)PO_(3)`.

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`H_(3)PO_(3)` on heating undergoes self-oxidation reduction, (i.e., disproportionation) to form `PH_(3)` in which P is reduced and `H_(3)PO_(4)` in which P is oxidised.
`underset("Orthophosphorous acid")overset(+3)(4H_(3)PO_(3))overset(Delta)tounderset("Phosphine")overset(-3)(PH_(3))+underset("Orthophosphoric acid")overset(+5)(3H_(3)PO_(4))`
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Give the disproportionation reaction of H_3PO_3 .

H_(3)PO_(3) is

(a) Give reasons : (i) H_(3)PO_(3) undergoes disproportionation reaction but H_(3)PO_(4) does not . (ii) When Cl_(2) reacts with excess of F_(2), ClF_(3) is formed and not FCl_(3) . (iii) Dioxygen is a gas while Sulphur is a solid at room temperature . (b) Draw the structure of the following : (i) XeF_(4) " " (ii) HClO_(3)

Give reasons : (a) H_(3)PO_(3) undergoes disproportination reaction but H_(3)PO_(4) does not (b) Dioxygen is a gas while sulphur is a solid (c ) When Cl_(2) reacts with excess of F_(2) compound formed is CiF_(3) " and not " FCl_(3) .

Give one disproportionation reaction of phosphorus acid (H_(3)PO_(3)) .