What will be the resultant products formed when the phosphorus hailde `PBr_(5)` splits up ?

Options

A. `[PBr_(4)]^(+)andBr^(-)`
B. `[PBr_(6)]^(-)and[PBr_(4)]^(+)`
C. `[PBr_(4)]^(+)`
D. `[PBr_(6)]^(-)`

Explanation

To determine the resultant products formed when phosphorus pentabromide (PBr₅) splits up, we need to analyze its structure and stability.

### Step-by-Step Solution:

1. **Understanding the Structure of PBr₅**:
- PBr₅ has a trigonal bipyramidal (TBP) geometry. This means it has five bromine atoms surrounding a central phosphorus atom, with three bromine atoms in a plane (equatorial positions) and two bromine atoms above and below this plane (axial positions).

**Hint**: Recall the geometry of PBr₅ and how it affects its stability.

2. **Stability of PBr₅**:
- PBr₅ is not very stable due to its geometry. The presence of large bromine atoms creates steric strain, making it more favorable for the molecule to break apart into more stable forms.

**Hint**: Consider why certain molecular geometries lead to instability.

3. **Dissociation of PBr₅**:
- When PBr₅ dissociates, it tends to lose one bromine atom. This results in the formation of phosphorus tetrabromide (PBr₄) and a bromide ion (Br⁻).

**Hint**: Think about how the loss of a bromine atom affects the phosphorus compound.

4. **Resultant Products**:
- The products formed from the dissociation of PBr₅ are:
- PBr₄ (phosphorus tetrabromide)
- Br⁻ (bromide ion)

**Hint**: Identify the products based on the number of bromine atoms remaining and their charges.

### Final Answer:
When phosphorus pentabromide (PBr₅) splits up, it forms phosphorus tetrabromide (PBr₄) and a bromide ion (Br⁻).

### Summary of Steps:
1. Identify the structure of PBr₅.
2. Assess its stability based on geometry.
3. Determine the dissociation process.
4. List the resultant products.