Two electrolytic cells containing silver nitrate solution and copper sulphate solution are connected in series. A steady currrent of 2.5 ampere was passed through them till 1.078 g of Ag were deposited. How long did the current flow? What weight of copper will be deposited? (At mass of Ag=107.8, Cu=63.5)

Explanation

To solve the problem step by step, we will use the formula for electrolysis:

### Step 1: Understand the formula
The formula used for calculating the weight of the metal deposited during electrolysis is:
\[ W = Z \times I \times T \]
Where:
- \( W \) = weight of the metal deposited (in grams)
- \( Z \) = electrochemical equivalent (in grams per coulomb)
...