If specific conductivity of N/50 KCl solution at 298 K is 0.002765 `ohm^(-1)cm^(-1)` and resistance of a cell containing this solution is 100 ohms, calculate the cell constant.

Explanation

To solve the problem, we need to calculate the cell constant using the given specific conductivity and resistance of the KCl solution. Here’s a step-by-step solution:

### Step 1: Understand the relationship between specific conductivity, conductance, and cell constant
The specific conductivity (κ) is related to the conductance (C) and the cell constant (L/A) by the formula:
\[ \kappa = C \times \frac{L}{A} \]
Where:
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