If a current of `0.5A` flows through a metallic wire for 2 hours, then how many electrons would flow through the wire ?

Explanation

Q (coulombs)=I(ampere)`xxt(sec)=(0.5" ampere")xx(2xx60xx60s)=3600C`
A flow of 1 F, i.e., 96500 C is equivaelent to flow of 1 mole of electrons, i.e., `6.02xx10^(23)` electrons
`therefore3600C` is equivalent to flow of electrons `=(6.02xx10^(23))/(96500)xx3600`
`=2.246xx10^(22)` electrons.