Home
Class 12
CHEMISTRY
A cell, Ag|Ag^(o+)||Cu^(2+)|Cu , initial...

A cell, `Ag|Ag^(o+)||Cu^(2+)|Cu` , initially contains `1 M Ag^(o+)` and `1M Cu^(2+)` ions. Calculate the change in the cell the potential after the passage of `9.65A` of current for `1h.`

Text Solution

Verified by Experts

Quantity of electricity passed passed=`9.65xx60xx60C=34740C`
`thereforeAg^(+)` ions deposited`=34740//96500" mole"=0.36` mole `(Ag^(+)+e^(-)toAg)`
`Cu^(2+)` ions deposited`=34740//(2xx96500)=0.18` mole `(Cu^(2+)+2e^(-)toCu)`
`therefore[Ag^(+)]"left"=1-0.36=0.64M`
`[Cu^(2+)]" left"=1-0.18=0.82M`
Cell reaction is: `Cu+2Ag^(+)toCu^(2+)+2Ag`
`DeltaE=E_(cell)^(@)=(0.0591)/(2)"log"([Cu^(2+)])/([Ag^(+)]^(2))=(0.0591)/(2)"log"(0.82)/((0.64)^(2))=8.89xx10^(-3)V`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANWER (Multiple Choice Questions-I)|90 Videos

  • ELECTROCHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANWER (Multiple Choice Questions-II)|7 Videos

  • ELECTROCHEMISTRY

    PRADEEP|Exercise HIGHER ORDER THINKING SKILLS|5 Videos

  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise IMPORTANT QUESTIONS|30 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    PRADEEP|Exercise Curiosity Questions|2 Videos

Similar Questions

Explore conceptually related problems

A cell Cu|Cu^(2+)||Ag^(o+)|Ag inintially contains 2 M Ag^(o+) and 2 M Cu^(2+) ion in 1L solution each . The change in cell potential after it has supplied 1A current for 96500 s is

The emf (E^(@)) of the following cels are : Ag|Ag^(+) (1 M)||Cu^(2+) (1 M)|Cu, E^(@)=-0.46 volt Zn|Zn^(2+) (1 M)||Cu^(2+) (1 M)|Cu, E^(@)=+1.10 volt Calculate the emf of the cell : Zn|Zn^(2+) (1 M)||Ag^(+) (1 M)|Ag

The e.m.f. ( E^(0) )of the following cells are Ag| Ag^(+)(1M) | | Cu^(2+)(1M) | Cu, E^(0) = -0.46V , Zn|Zn^(2+)(1M)| | Cu^(2+)(1M) | Cu : E^(0) = +1.10V Calculate the e.m.f. of the cell Zn | Zn^(2+)(1M) | | Ag^(+)(1M) | Ag