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The equivalent conctance at infinite dil...

The equivalent conctance at infinite dilution of the salt MX is 160.84 `ohm^(-1)cm^(2)eq^(-1)`. If the transport number of `M^(+)` is 0.40, calculate the ionic mobility of the ion.

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To solve the problem, we need to calculate the ionic mobility of the ion \( M^+ \) given the equivalent conductance at infinite dilution of the salt \( MX \) and the transport number of \( M^+ \). ### Step-by-Step Solution: 1. **Identify Given Data**: - Equivalent conductance at infinite dilution (\( \Lambda^0 \)) of salt \( MX = 160.84 \, \Omega^{-1} \, cm^2 \, eq^{-1} \) - Transport number of \( M^+ \) (\( t_{M^+} = 0.40 \)) ...
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