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Two Faraday of electricity is passed thr...

Two Faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is (at. Mass of Cu=63.5u)

A

2 g

B

127 g

C

0 g

D

63.7 g

Text Solution

Verified by Experts

The correct Answer is:
D
`Cu^(2+)+2e^(-)toCu`
Thus, 2F charge deposit 1 mol of Cu, i.e., 63.5g.
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