A current is passed through two cells connected in series. The first cell contains `X(NO_(3))_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))` . The relative atomic masses of X and Y are in the ratio `1:2`. What is the ratio of liberated mass of X to that of Y ?

Options

A. `3:2`
B. `1:2`
C. `1:3`
D. `3:1`

Answer

C

Explanation

if atomic mass of X=a, then that of Y=2a. As eq.wt=atomic mass/valency,
Eq. wt. of X=a/3, Eq. wt. of Y=2 a/2=a.
`("Mass of "X)/("Mass of "Y)=("Eq. wt. of "X)/("Eq. wt. of Y")=(a//3)/(a)=(1)/(3)=1:3`