When `0.1 mol MnO_(4)^(2-)` is oxidized the quantity of electricity required to completely oxidize `MnO_(4)^(2-)` to `MnO_(4)^(-)` is

Options

A. 96500 C
B. `2xx96500C`
C. `9650C`
D. `96.50C`

Answer

C

Explanation

The oxidation reaction is
`MnO_(4)^(2-)toMnO_(4)^(-)+e^(-)`
1 mol of `MnO_(4)^(2-)` for oxidation requires electricity=1F=96500C
`therefore0.1` mol of `MnO_(4)^(2-)` will require electricity =9650C