The weight of silver (at wt. = 108) disp...

The weight of silver (at `wt. = 108`) displaced by a quantity of electricity which displaced `5600 mL` of `O_(2)` at `STP` will be:

5.4 g

10.8 g

54.0 g

108.0 g

Text Solution

Verified by Experts

The correct Answer is:

By Faraday's second law, `(W_(Ag))/(W_(O_(2)))=(E_(Ag))/(E_(O_(2)))`
Weight of 5000 mL of `O_(2)` at STP
`=(32)/(22400)xx5600=8g`
`therefore(W_(Ag))/(8)=(108)/(8)` or `W_(Ag)=108g`

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