The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `6xx10^(23)`
B. `6xx10^(20)`
C. `3.75xx10^(20)`
D. `7.48xx10^(23)`

Answer

C

Explanation

Charge flowing during electrolysis`=Ixxt`
`=1xx60=60` coulombs
But charge flowing=number of electrons flowing`xx`charge on each electron
`therefore60=nxx1.60xx10^(-19)`
or `n=(60)/(1.60xx10^(-19))=37.5xx10^(19)=3.75xx10^(20)`