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Given E(Cr^(3+)//Cr^(@))= -O*74V,E(MnO(4...

Given `E_(Cr^(3+)//Cr^(@))= -O*74V`,`E_(MnO_(4)^(-)//Mn^(2+))^(@) = 1.51V`
`E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)`= 1.33V , `E_(Cl//Cl^(-))^(@)= 1.36V`
Based on the given above , Strongest oxidising agent will be:

A

`MnO_(4)^(-)`

B

`Cl^(-)`

C

`Cr^(3+)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
A
Higher the reduction potential, more easily it is reduced and hence stronger is the oxidizing agent. As reduction potential of `MnO_(4)^(-)//Mn^(2)` is maximum, hence it is strongest oxidizing agent.
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