Given `E_(Cl_(2)//Cl^(-))^(@)=1.36V,E_(Cr^(3+)//Cr)^(@)=-0.74V`
`E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V`
Among the following, the strongest reducing agent is

Options

A. `Cr^(3+)`
B. `Cl^(-)`
C. `Cr`
D. `Mn^(2+)`

Answer

C

Explanation

Greater the standard oxidation potential (or lesser is the standard reduction potential), more easily the substance is oxidized and hence stronger is the reducing is oxidized and hence stronger is the reducing agent. As `E_(Cr^(+3)//Cr)^(@)` (i.e., standard reduction potential) is lowest, hence, Cr will be strongest reducing agent.