`Zn` gives `H_(2)` gas with `H_(2)SO_(4)` and `HCl` but not with `HNO_(3)` because

Options

A. `Zn` acts as oxidizing agent when reacts with `HNO_(3)`
B. `HNO_(3)` is weaker acid than `H_(2)SO_(4)` and HCl
C. In electrochemical series, Zn is above hydrogen
D. `NO_(3)^(-)` is reduced in preference to hydronium ion

Answer

B

Explanation

In the given reaction, `I^(-)` has been oxidized to `I_(2)` and `Cr_(2)O_(7)^(2-)` ions have been reduced to `Cr^(3+)`
`thereforeE_(cell)^(@)=E_(Cr_(2)O_(7)^(2-))^(@)-E_(I_(2))^(@)`
i.e., `0.79=1.33-E_(I_(2))^(@)` or `E_(I_(2))^(@)=0.54V`