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The EMF of a cell formed by combining a ...

The EMF of a cell formed by combining a particular electrode with standard calomel electrode is found to be 0.344 V and calomel electrode is found to act as cathode. If the same electrode is combined with standard hydrogen electrode, the EMF of the cell will be (Given standard reduction potential, `E_("calomel")^(@)=+0.244V`)

A

0.344V

B

0.244 V

C

0.588 V

D

0.100 V

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The correct Answer is:
To solve the problem step by step, we need to determine the EMF of the cell when the particular electrode is combined with the standard hydrogen electrode (SHE). ### Step 1: Understand the given information - EMF of the cell with the calomel electrode (acting as cathode) = 0.344 V - Standard reduction potential of the calomel electrode, \( E_{\text{calomel}}^{\circ} = +0.244 \, \text{V} \) ### Step 2: Identify the roles of the electrodes Since the calomel electrode acts as the cathode in the first cell, we can denote: - \( E_{\text{cathode}} = E_{\text{calomel}}^{\circ} = +0.244 \, \text{V} \) - Let the potential of the particular electrode be \( E_{\text{anode}} \). ### Step 3: Use the EMF formula for the cell The EMF of the cell can be expressed as: \[ E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} \] Substituting the known values: \[ 0.344 \, \text{V} = 0.244 \, \text{V} - E_{\text{anode}} \] ### Step 4: Solve for \( E_{\text{anode}} \) Rearranging the equation gives: \[ E_{\text{anode}} = 0.244 \, \text{V} - 0.344 \, \text{V} \] \[ E_{\text{anode}} = -0.100 \, \text{V} \] ### Step 5: Calculate the EMF when combined with SHE The standard reduction potential of the standard hydrogen electrode (SHE) is: \[ E_{\text{hydrogen}}^{\circ} = 0 \, \text{V} \] When the particular electrode (acting as anode) is combined with SHE, the EMF of the cell will be: \[ E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} = E_{\text{hydrogen}}^{\circ} - E_{\text{anode}} \] Substituting the values: \[ E_{\text{cell}} = 0 \, \text{V} - (-0.100 \, \text{V}) \] \[ E_{\text{cell}} = +0.100 \, \text{V} \] ### Final Answer The EMF of the cell when the particular electrode is combined with the standard hydrogen electrode is: \[ \boxed{0.100 \, \text{V}} \]

To solve the problem step by step, we need to determine the EMF of the cell when the particular electrode is combined with the standard hydrogen electrode (SHE). ### Step 1: Understand the given information - EMF of the cell with the calomel electrode (acting as cathode) = 0.344 V - Standard reduction potential of the calomel electrode, \( E_{\text{calomel}}^{\circ} = +0.244 \, \text{V} \) ### Step 2: Identify the roles of the electrodes Since the calomel electrode acts as the cathode in the first cell, we can denote: ...
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