A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl or `pH = 10` and by passing bydrogen gas around the platinum wire at one atm pressure . The oxidation potential of electrode would be ?

Options

A. 0.059 V
B. 0.59 V
C. 0.118 V
D. 0.18 V

Answer

C

Explanation

For hydrogen electrode, reduction reaction is
`H^(+)+e^(-)to(1)/(2)H_(2)`
`E_(H^(+)//(1)/(2)H_(2))^(@)=E_(H^(+)//(1)/(2)H_(2))^(@)-(0.0591)/(n)"log"(p_(H_(2))^(1//2))/([H^(+)])`
`=0-(0.0591)/(n)"log"(1)/(10^(-10))=-0.591`
`(pH=10" means "[H^(+)]=10^(-10)M)`
`therefore`Oxidation potential`=0.591V`