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The cell , Zn | Zn^(2+) (1M) || Cu^(2+) ...

The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

A

`9.65xx10^(4)`

B

antilog 24.08

C

`37.3`

D

`10^(37.3)`

Text Solution

Verified by Experts

The correct Answer is:
B

The cell reaction is: `Zn+Cu^(2+)toZn^(2+)+Cu` when the cell is completely discharged, `E_(cell)^(@)=(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
i.e., `1.10=(0.591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
or `([Zn^(2+)])/([Cu^(2+)])=37.3` or `([Zn^(2+)])/([Cu^(2+)])=10^(37.3)`
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