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The value of (E(H(2)O)//H(2)^(@)) (1atm)...

The value of `(E_(H_(2)O)//H_(2)^(@))` (1atm) Pt at 298K would b e

A

`-0.207V`

B

`+0.207V`

C

`-0.414V`

D

`+0.414V`

Text Solution

Verified by Experts

The correct Answer is:
C
For water at 298K,`[H^(+)]=10^(-7)M`
Reduction reaction is: `H^(+)+e^(-)to(1)/(2)H_(2)`
`thereforeE=-(RT)/(F)"ln"(p_(H_(2))^(1//2))/([H^(+)])=-0.0591"log"(p_(H_(2))^(1//2))/([H^(+)])`
`=0.0591"log"(1)/(10^(-7))=-0.4137=-0.414V`
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