Find `K_(c)` for the complex`:`
`[Ag(NH_(3))_(2)]^(o+)hArrAg^(o+)+2NH_(3)`
`E^(c-)._((Ag^(o+)//Ag))=0.8V` and `E^(c-)._{[Ag(NH_(3))_(2)]^(o+)|Ag|NH_(3))=0.37V`

Options

A. `10^(-8)`
B. `10^(-10)`
C. `10^(-12)`
D. `10^(-14)`

Answer

D

Explanation

`[Ag(NH_(3))_(2)}^(+)+e^(-)toAg+2NH_(3),E^(@)=0.02V`
`underline(" "AgtoAg^(+)+e^(-),E^(@)=-0.80V)`
`[Ag(NH_(3))_(2)]^(+))hArr[Ag^(+)]+2NH_(3),E_(cell)^(@)=-0.78V`
`E_(cell)^(@)=(0.0591)/(n)logKtherefore-0.78=(0.0591)/(1)logK`
or `logK=(-0.78)/(0.0591)=--13.2`
K=Antilog`overline(14).8=6.3xx10^(-14)`