Give the relationship between the equivalent weight and molecular weight of `KMnO_(4)` in ( a) acidic (b) alkaline and (c ) neutral media.

Explanation

To find the relationship between the equivalent weight and molecular weight of potassium permanganate (KMnO₄) in different media (acidic, alkaline, and neutral), we need to analyze the redox reactions that occur in each medium and determine the number of electrons involved in the reactions.

### Step-by-Step Solution:

**(a) In Acidic Medium:**
1. **Identify the Reaction:**
In acidic medium, KMnO₄ acts as an oxidizing agent. The half-reaction can be written as:
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