One among the langthanides ,Ce(III), can be easily oxidized to Ce(IV)(At. No. of `Ce= 58)` . Explain why ? Or Of the lanthanides, cerium (At. No. 58) forms a tetrapositive ion, `Ce^94+)` in aqueous solution. Why?

Explanation

To understand why cerium (Ce) can be easily oxidized from Ce(III) to Ce(IV), we need to look at its electronic configuration and the stability of its oxidation states.

### Step-by-Step Solution:

1. **Identify the Atomic Number and Electronic Configuration of Cerium:**
- Cerium has an atomic number of 58. Its electronic configuration can be written as:
\[
\text{Ce: } [Xe] 6s^2 4f^1
...