`{:(,"Column I(Substance)",,"Column II(Eq. wt)"),((A),KMnO_(4)"in acidic solution",(p),"Mol."wt//6),((B),KMnO_(4)"in alkaline solution",(q),"Mol." wt//5),((C ),KMnO_(4)"in neutral solution",(r ),"Mol."wt//3),((D),K_(2)Cr_(2)O_(7)" in acidic medium ",(s ),"Mol. "wt//1):}`

Options

A. `A-s,B-r,C-q,D-p`
B. `A-q,B-s,C-r,D-p`
C. `A-r, B-s,C-p,D-q`
D. `A-p, B-s,C-q,D-r`

Explanation

To solve the problem of matching the substances in Column I with their equivalent weights in Column II, we will follow these steps:

### Step 1: Understand the concept of equivalent weight
The equivalent weight of a substance is calculated using the formula:
\[ \text{Equivalent Weight} = \frac{\text{Molecular Weight}}{\text{N factor}} \]
where the N factor is the change in oxidation state of the element involved in the reaction.
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