If magnification, `m =-1`
`v=50`cm
If the magnification has minus sign, then the image is real and inverted,
`therefore v=-50`(for real image)
`therefore m=(-v)/(u) " " rArr cancel(-)=(cancel(-)(-50))/(cancel(-)u) " " rArr u =-50`cm
(a) Since image is formed on the secreen therefore the mirror formed real image which is formed by concave mirror only.
(b) Image distance = 50 cm in front of the mirror.
(c) `(1)/(f)=(1)/(v)+(1)/(u)" "rArr " "(1)/(f)=(1)/(-50)+(1)/(-50)`
`(1)/(f)=-(1)/(50)-(1)/(50)" " rArr (cancel(-2))/(cancel(l50))=(-1)/(25)`
`therefore f =-25` cm
(d) Ray diagram:
