Two resistance `R_(1) = 10` ohm and `R_(2) = 10` ohm are to be connected with 20V battery. Out of which of the following maximum current will flow. Calcuate its magnitude.

Explanation

In all the three cases, the same current will be flowing as in all the three cases. Both the resistors are combined in series.
`R_(1)=10 Omega" " R_(2)=10Omega`
Resultant `R=R_(1)+R_(2)=10+10=20Omega`
`V=20 V`
`I=(V)/( R) = (20)/(20) = 1A`