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An electric lamp of resistance 2 Omega a...

An electric lamp of resistance `2 Omega` and a conductor of resistance `4 Omega`are connected to a
`6 V` Battery as shown in the circuit. Calculate:
(a) the totak resistance of the circuit,
(b) the current through the circuit,
(c) the potential difference across the (i) electric lamp
and (ii) conductor, and
(d) power of the lamp.

Text Solution

Verified by Experts

`R_(1)=20 Omega, R_(2) = 4 Omega, V=6V`
(a) Total resistance, `R= R_(1) + R_(2) = 20 +4 = 24 Omega`
(b) Current, `I=V/R = 6/24=1/4=0.25A`
(c) Potential difference across
(i) Electric lamp, `V_(1)=IR_(1)=0.25xx 20 =5 "volts"`
(ii) Conductor, `V_(2)=IR_(2)=0.25xx 4 =1 "volt"`
(d) Power of the lamp, `P=VI=6xx0.25=1.5 W … where[V=V_(1)+V_(2)]`
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