` lim_( x to 1) ( (log g)/(1-x))` का मान ज्ञात कीजिए ।

Explanation

` x = 1 + h ` रखो , जबकि h बहुत ही छोटा है ।
अतः ` lim _( x to 1) ( log x)/( 1-x) = lim _( h to 0) ( log ( 1+ h))/(-h) `
` = lim _( h to 0) (h-h^(2)/2 + h^(3)/2 - . . . . .)/(-h)`
` = lim_( h to 0) -(1- h/2 + h^(2)/3 - . . . .. )" " (जब h != 0) `
` -1`