फलन ` x^(n)/(log_(e^(x)))` का x के साक्षेप अवकल गुणांक ज्ञात कीजिए ।

Explanation

`d/(dx) { (x^(n))/(log_(e)x}}= ( log_(e)xd/(dx)x^(n) - x^(n) d/(dx) log_(e)x)/( log_(e)x)^(2)`
` = ( log_(e) x. nx^(n-1) -x^(n) . 1/x)/( log_(e)x)^(2)`
` = ( nx^(n-1) log_(e)x-x^(n-1))/( log_(e)x)^(2)`
` = ( x^(n-1) ( nlog _(e) x-1))/( log_(e)x)^(2)`