बिंदु `(2,0,-3)` पर कार्यरत बल `vecF=4hati+5hatj-6hatk` का बिंदु (2,-2,-2) के परितः आघूर्ण होगा:

Options

A. `-8hati-4hatj-7hatk`
B. `-7hati-4hatj-8hatk`
C. `-7hati-8hatj-4hatk`
D. `-4hati-hatj-8hatk`

Explanation

`vecF=rhati+5hatj-6hatk`
`vecr=(2-2)hati+[0-(-2)hatj+[-3-(-2)]hatk`
`=2hatj-hatk`
`vec(tau)=vecrxxvecF`
`=(2hatj-hatk)xx(4hati+5hatj-6hatk)`
`=|(hati,hatj,hatk),(0,2,-1),(4,5,-6)|=-7hati-4hatj-8hatk`