`(dy)/(dx)=tan^2(x+y)`

Solve the following initial value problem: (dy)/(dx)=tan2x,y(0)=2

The solution of the differential equation 2x^2y(dy)/(dx)=tan(x^2y^2)-2x y^2, given x=1, y=pi/2, is

The solution of the differential equation 2x^2y(dy)/(dx)=tan(x^2y^2)-2x y^2, given y(1)=pi/2, is

The solution of the differential equation 2x^2y(dy)/(dx)=tan(x^2y^2)-2x y^2, given y(1)=pi/2, is

Solve the following initial value problem: (dy)/(dx)=y \ tan2x ,\ y(0)=2

(dy)/(dx) +2x tan(x-y) = 1 rArr sin(x-y) =

For the differential equation, find a particular solution satisfying the given condition: (dy)/(dx) = y tan x, y = 2 when x = 0

The solution of the differential equation 2x^(2)y(dy)/(dx) = tan(x^(2)y^(2))-2xy^(2) , given y(1) = sqrt(pi/2) , is

The solution of the differential equation 2x^(2)y(dy)/(dx)=tan(x^(2)y^(2))-2xy^(2), given y(1)=(pi)/(2), is

The solution of the differential equation 2x^(2)y(dy)/(dx) = tan(x^(2)y^(2))-2xy^(2) , given y(1) = sqrt(pi/2) , is