Find the centre and the radius of the circle `x^2+y^2+8x+10 y-8=0`.

Explanation

`x^2 + y^2 + 8x + 10y - 8 =0`

`x^2 + 8x + 16 -16 + y^2 + 10y +25- 25 - 8=0`

`(x+4)^2 - 16 + (y+ 5)^2 - 25 -8=0`

`(x+4)^2 + (y+5)^2 = 33+ 16`

`(x+4)^2 + (y+5)^2 = (7)^2`

so centre is `(h,k) = (-4,-5)`

radius `= 7`units

answer