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If vec a,vec b , vec c are unit vectors ...

If `vec a,vec b , vec c` are unit vectors such that `veca + vec b+ vecc = 0` and `lambda = veca.vecb + vecb.vecc+vecc.veca `and `d = veca xx vecb + vecb xx vecc + vecc xx veca`, then `(lambda,vecd)` is

A

`(-(3)/(2), 3veccxxvecb)`

B

`((3)/(2), 3vecaxxvecc)`

C

`((3)/(2), 3vecbxxvecc)`

D

`(-(3)/(2), 3vecaxxvecb)`

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The correct Answer is:
`D`
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