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Calculated the mass of FeSO(4).7H(2)O, w...

Calculated the mass of `FeSO_(4).7H_(2)O`, which must be added in 100 kg of wheat to get 10 PPM of Fe.

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The correct Answer is:
4.96 g
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What is the molarity of a FeSO_(4) . 7H_(2) O solution having 5.56 of it dissolved in 250 mL of water ? ( molar mass =278)

25 grams of a sample of ferrous sulphate is dissolved in dilute sulphuric acd. By adding water, its volume is made up to 1 litre. 25 mL of this solution requries 20 mL of N//10 KMnO_(4) solution for oxidation. Calculate the percentage of FeSO_(4) . 7H_(2)O in the sample. Strategy: Percentage of FeSO_(4).7H_(2)O =("mass"_("ferrous sulphate"))/("mass of sample")xx100% To get the mass of ferrous suphate, we need to calculate equivalents of ferrous sulphate. By law of equivalrnce, the milli equivalents of KMnO_(4) must be equal to the miliequivalents of ferrous sulphate. We can find the milliequivalents of KMnO_(4) by taking the product of millilitres of solution and its normality.

The amount of FeSO_(4).7H_(2)O to be weighted to prepare a solution of 100 ml of 0.1 M concentration is (Mol.wt.of FeSO_(4) . 7H_(2)0=278)

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