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Ellipse 2x^2+ y^2 = 1 and y = mx meet a ...

Ellipse `2x^2+ y^2 = 1` and `y = mx` meet a point A in first quadrant. Normal to the ellipse at P meets x-axis at `(-1/(3sqrt2),0)` and y-axis at `(0, beta)`, then `|beta|` is

A

`(2sqrt2)/(3)`

B

`(2)/(sqrt3)`

C

`(sqrt2)/(3)`

D

`(2)/(3)`

Text Solution

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The correct Answer is:
C
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