Lacto bacillus has generation time 60 min. at 300 K and 40 min. at 400 K. Determine activation energy in `(kJ)/(mol)` . (`R = 8.3 J K^ (–1) mol^(–1)` ) `[ log_e (2/3) = - 0.4 ]`

A first order reaction is 50% completed in 40 minutes at 300 K and in 20 minutes at 320 K. Calculate the activation energy of the reaction . (Given : log 2 = 0.3010 , log 4 = 0.6021 , R = 8.314 J K^(-1) mol^(-1) ) .

The rate temperature changes from 300K to 310K. Activation energy of such a reaction will be (R = 8.314 JK^(-1) mol^(-1) " and " log 2 = 0.3010)

The rate of a reaction doubles when its temperature changes form 300 K to 310 K . Activation energy of such a reaction will be: (R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)

A sample of milk splits after 60 min . At 300 K and after 40 min 400K when the population of lactobacillus acidophilus in it doubles . The activation energy (in KJ/mol) for this process is closest to (Given , R = 8.3 J mol^(-1) K^(-1), " ln" (2/3) = 0.4 , e^(-3) = 4.0)

The rate of a reaction doubles when the tempeature changes from 300 K to 310 K. Activation energy for the reaction is: (R = 8.314 JK^(-1) mol^(-1), log2 = 0.3010)

The rate constant of a first orrder reaction becomes six times when the temperature is raised from 350 K to 400 K. Calculate the activation energy of the reaction (R=8.314" JK"^(-1)" mol"^(-1))