An unbiased die is tossed twice. Find the probability of getting a 4, 5 or 6 on the first toss and a 1, 2, 3 or 4 on the second toss.

Options

A. `(1)/(3)`
B. `(2)/(3)`
C. `(3)/(4)`
D. `(5)/(6)`

Answer

A

Explanation

Here `S={1,2,3,4,5,6}` Let A ={4,5,6} and B={1,2,3,5}
`:. P(A) =(3)/(6)=(1)/(2) " and "P(B) =(4)/(6) =(2)/(3)`
Clearly A and B are independent events
`:. P(A nnB) =P(A) xx P(B) =((1)/(2)xx(2)/(3)) =(1)/(3)`