सिद्ध कीजिये कि फलन ` f ( x ) = x ^2- 7x + 3 ` बिंदुओं ` x = 1, x = 2, x = 3 ` पर सतत है |

Explanation

` f ( 1-0 ) = lim_ ( hto 0) f ( 1 - h ) = lim _ ( hto0 ) [ ( 1 - h ) ^(2) - 7 ( 1- h ) + 3 ] `
` = lim _ ( hto 0 ) ( - 3+ h^2 + 5h ) = - 3 `
और ` f ( 1 + 0 ) = lim _ ( hto 0 ) f ( 1 + h) = lim_ ( hto 0 ) [ ( 1 + h )^2 - 7 ( 1 + h ) + 3 ] = - 3 `
` f (1) = 1 ^2 - 7 xx 1 + 3 = - 3 `
स्पष्टतः ` f ( 1 + 0 ) = f ( 1 - 0 ) = f ( 1 ) `