अवकल समीकरण `(1+x^(2))sec^(2)ydy+2xtanydx=0` को हल कीजिये।
दिया है कि `y=(pi)/(4)` जब x=1

Explanation

`(1+x^(2))sec^(2)ydy+2xtanydx=0`
`implies(sec^(2)y)/(tany)dy+(2x)/(1+x^(2))dx=0`
समाकलन करने पर,
`int(sec^(2)y)/(tany)dy+(2x)/(1+x^(2))dx=0`
`implieslogtany+log(1+x^(2))=c`
यदि `y=(pi)/(4)" तथा "x=1" तब "c=logtan""(pi)/(4)+log(1+1)`
`impliesc=log2`
`logtany+log(1+x^(2))=log2`
`:.log[(1+x^(2)).tany]=log2`
`:.tany=(2)/(1+x^(2))`