Find derivative of the following functions: `(secx-1)/(secx+1)`

Explanation

To find the derivative of the function \( y = \frac{\sec x - 1}{\sec x + 1} \), we will use the quotient rule of differentiation. The quotient rule states that if you have a function \( y = \frac{f(x)}{g(x)} \), then the derivative \( y' \) is given by:

\[ y' = \frac{f'(x)g(x) - f(x)g'(x)}{(g(x))^2} \]

where \( f(x) = \sec x - 1 \) and \( g(x) = \sec x + 1 \).

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