Two elastic wire `A & B` having length `l_(A)=2m` and `l_(B)=1.5m` have young's modules ratio `(Y_(A))/(Y_(B))=(7)/(4)`. If `r_(B)=2mm` then the radius of `A` given that due to application of the same force change in length in both `A & B` is same
Two wires A and B have Young moduli in the ratio 1:2 and ratio of lenghts is 1:1 . Under the application of same stress the ratio of elonagations is
Two wires A & B of same material having elongation 2mm and 4mm resp. on applying 2N take. If radius of B is 4 times the radius of A and ratio of length of A is to B in the form of 1/x then the value of x is.
The length of a wire is increased by 1 mm due to applied load. The wire of the same material have lengths and radius half that of the first wire, by the application of the same force, then extension produced will be
Two wires of different materials having Young's moduli in the ratio 3 : 5, lengths in the ratio 2 :1 and diameters in the ratio 1 : 2 are stretched with the same force. The ratio of stress in the wires is
Two wires of different materials having Young's moduli in the ratio 3 : 5, lengths in the ratio 2 :1 and diameters in the ratio 1 : 2 are stretched with the same force. The ratio of stress in the wires is
Two wires A and B of same material have radii in the ratio 2:1 and lengths in the ratio 4:1 . The ratio of the normal forces required to produce the same change in the lengths of these two wires is
Two wires A and B are of the same material. Their lengths are in the ratio 1 : 2 and the diameter are in the ratio 2 : 1. If they are pulled by the same force, then increase in length will be in the ratio
