Acell of internal resistance r drives a current through an external resistance R . The power delivered by the cell to the external resistance is maximum when
A battery has an emf E and internal resistance r. A variable resistance R is connected across the terminals of the battery. Find the value of R such that (a) the current in the circuit id maximum (b) the potential difference across the terminals is maximum.
If a battery of emf E and internal resistance r is connected across a load of resistance R . Shot that the rate at which energy is dissipated in R is maximum when R = r and this maximur power is P = E^2//4r .
A battery of emf epsilon and internal resistance r is connected across a load resistance R_L . The plot between output power and load resistance is shown in the figure The value of emf epsilon and internal resistance r respectively will be
A battery of emf E and internal resistance r is connected is to external resistance B The maximum point is the external circuit is 9W The current flowing in the circuit under the condition is 3A What is the value of E in volt ?
An accumulator of emf epsilon and internal resistance r is first connected to an external resistance R_(1) and then to an external resistance R_(2) for the same time. For what value of r the beats dissipated in R_(1) and R_(2) will be same?
An accumulator of emf epsilon and internal resistance r is first connected to an external resistance R_(1) and then to an external resistance R_(2) for the same time. For what value of r the beats dissipated in R_(1) and R_(2) will be same?
A battery of emf (epsilon) and internal resistance r is connected across a load resistance R_L The plot between output power and load resistance is shown in the figure. value of emf (epsilon) and internal resistance respectively will be
Two cells , each of emf E and internal resistance r , are connected in parallel across a resistor R . The power delivered to the resistor is maximum if R is equal to
