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The time period of a simple pendulum in ...

The time period of a simple pendulum in air is `T`. Now the pendulum is submerged in a liquid of density `(rho)/(16)` where `rho` is density of the bob of the pendulum. The new time period of oscillation is.

A

`(4)/(sqrt(15))T`

B

`sqrt((4)/(15))T`

C

`sqrt((15)/(4))T`

D

`(sqrt(15))/(3)T`

Text Solution

Verified by Experts

The correct Answer is:
A
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